← 返回学习笔记:算法2026-01-08 ·1 min ·29 字#算法 #学习用最直观的方法理解时间复杂度。代码片段def two_sum(nums, target): seen = {} for i, n in enumerate(nums): if target - n in seen: return [seen[target - n], i] seen[n] = i 图片与链接相关链接:LeetCode上一篇工程复盘下一篇小站优化